What Electric Field is Needed to Undeflect Electrons in a Magnetic Field?

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SUMMARY

The discussion focuses on calculating the electric field required to undeflect electrons in a magnetic field. A beam of electrons is accelerated through a potential difference of 11 kV, resulting in a kinetic energy of 11,000 eV. The magnetic field strength is given as 0.05 T. To find the necessary electric field (E), the velocity (v) of the electrons must first be determined using the relationship E = vB, where B is the magnetic field strength.

PREREQUISITES
  • Understanding of electron acceleration through potential differences
  • Familiarity with the Lorentz force equation (F = qvB)
  • Knowledge of electric field concepts (E = qE)
  • Basic principles of kinetic energy in relation to voltage
NEXT STEPS
  • Calculate the velocity of electrons accelerated through an 11 kV potential difference
  • Explore the relationship between kinetic energy and electric potential energy
  • Learn about the Lorentz force and its applications in particle physics
  • Investigate the principles of velocity selectors in electromagnetic fields
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Physics students, electrical engineers, and anyone interested in the behavior of charged particles in electromagnetic fields.

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A beam of electrons is accelerated through a potential difference of 11kV before entering a velocity selector. If the B-field of the velocity selector is perpendicular to the velocity and has a value of 0.05 T, what value of the E-field is required (in the magnetic field region) if the particles are to be undeflected?

What I know:
F = qvB
and
F = qE

Therefore E = vB

But how on Earth do I find the velocity? Please help!
 
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Stryker321 said:
But how on Earth do I find the velocity? Please help!

Read this again:
"A beam of electrons is accelerated through a potential difference of 11kV"
What energy will the electrons have?
 

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