# What equation to use for simple kinetics quesitons?

• Alipepsi
In summary: You can check for yourself by substituting your formula for t back into the original equation to see if everything cancels out algebraically. Or you can use it to calculate t, then substitute it and your given quantities back into the original equation to see if everything cancels out numerically.
Alipepsi
For the questions below, which kinematic equations would I use? I have already tried these on my own but can not find a way to match the answers with the answer sheet, the answers on the answer key are RIGHT, as they are approved by my teacher.
Okey so the questions are
1) A baseball is thrown up vertically at 25m/s. What velocity will the ball have after:
a)1.0s
b)2.0s
c)3.0s

2) A soccer ball is kicked straight up at a speed of 30m/s. How long will it take to reach a height of 5.0m?
It would be great if you showed me how you got your answers, if not, I will really appreciate the equations, THANKS!

Welcome to PF!

Hi Alipepsi! Welcome to PF!

For both questions, use one of the standard constant acceleration equations.

If you're still stuck, show us what you've tried, and then we'll know how to help!

Thanks

Tiny, I'am confused =(
I've looked over the equations but can not figure out what equation to use. PLEASE HELP ME I have a test after march break =S

For 1), you have u t and a, and you want v

For 2), you have u s and a, and you want t

So which of the constant acceleration equations has only u t a and v,

and which has only u t a and s ?

a=vf-vi/t

Then just derive it :P

Yup!

(And the other one? )​

Vf^2=vi^2+2a(d)
v=sq root 30^2-2(9.81)(5)
v= 28.3m

THEN

Solve for time using the equation: t=(v-vf)/a

THANKS FOR YA HELP MAN! :D

You're welcome!

But quicker would have been s = ut + 1/2 at2

I see, can you help me with how to know what equations to use for questions. Like I was confused for what equation to use for the second problem. Do I look for all the values I'am given with the values in all teh equatiosn then pick the one? Ik my quesitons is silly :P

I always write down a list of all the given values when I start a problem. Then I compare them to the equations that I know.

tiny-tim said:
You're welcome!

But quicker would have been s = ut + 1/2 at2

So you have to derive for t right?

This is what I got:

t= sq root s-ut/0.5a

This is correct? Really need to know this asap

yes, you'd have to solve for t

SHISHKABOB said:
yes, you'd have to solve for t

did I derive for t correctly there?

you'd have to use the quadratic equation to solve for t in that case.

notice how t= sq root s-ut/0.5a still has a t ion both sides of the equation.

SHISHKABOB said:
you'd have to use the quadratic equation to solve for t in that case.

notice how t= sq root s-ut/0.5a still has a t ion both sides of the equation.

If I was to use quadratic, then how would I get my A, B, and C values from solving that equation?

well the equation is also this:

1/2 at2 + ut - s = 0

so if t is the variable, what are the constants?

Alipepsi said:
did I derive for t correctly there?

You can check for yourself by substituting your formula for t back into the original equation to see if everything cancels out algebraically. Or you can use it to calculate t, then substitute it and your given quantities back into the original equation to see if everything cancels out numerically.

## 1. What is the general equation for simple kinetics questions?

The general equation for simple kinetics questions is Rate = k[A]^m[B]^n, where k is the rate constant, [A] and [B] are the concentrations of the reactants, and m and n are the orders of the reactants.

## 2. How do I determine the order of a reactant in a kinetics equation?

The order of a reactant in a kinetics equation can be determined experimentally by varying the concentration of the reactant while keeping all other factors constant. The order is then determined by analyzing the change in the rate of the reaction with respect to the change in concentration of the reactant.

## 3. What is the difference between zero-order, first-order, and second-order kinetics?

In zero-order kinetics, the rate of the reaction is independent of the concentration of the reactants. In first-order kinetics, the rate is directly proportional to the concentration of one reactant. In second-order kinetics, the rate is directly proportional to the product of the concentrations of two reactants.

## 4. Can the rate constant, k, change in a simple kinetics equation?

Yes, the rate constant, k, can change in a simple kinetics equation. It is affected by factors such as temperature, pressure, and the presence of a catalyst. Changing these factors can alter the value of k, and therefore, the rate of the reaction.

## 5. How can I use the kinetics equation to determine the rate of a reaction?

To determine the rate of a reaction using the kinetics equation, you will need to know the concentrations of the reactants, the order of the reaction, and the rate constant. Plug these values into the equation Rate = k[A]^m[B]^n and solve for the rate. This will give you the rate of the reaction at a specific point in time.

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