What equations can I use to find the tension in this cable? Transverse pulse ?

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SUMMARY

The discussion focuses on calculating the tension in a cable using the equation for wave velocity in a medium. The user provided specific parameters: mass (0.180 kg), length (4.20 m), and the time for four trips (0.845 s). The derived equations include the wave velocity equation, v = √(T/μ), where μ is the linear mass density calculated as μ = m/L. The final tension calculated is 67.8 N, confirming the correct application of the equations.

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riseofphoenix
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What equations can I use to find the tension in this cable?? "Transverse pulse"??

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I know I'm given the following but I have no idea what equation to use...does anyone know?

Mass: m = 0.180 kg
Length: L = 4.20 m
μ = mass (m) / unit length of cord (L)​
Time for 4 trips down and back: 0.845 s
Tension: T = ? N

1) Equation to use: v = √(T/μ)

2) First find v and μ

v = distance/time
v = 2(4 trips)/0.845 s
v = 8/0.845
v = 9.467
valong the cord = 9.467(L)
valong the cord = 9.467(4.20 m)
valong the cord = 9.467(4.20 m)
valong the cord = 39.76331361 m/s

μ = m/L
μ = (0.180 kg)/(4.20 m)
μ = 0.042857

3) Plug everything in equation v = √(T/μ) and solve for T

(v)2 = [√(T/μ)]2
v2 = T/μ
μv2 = T
0.042857(39.763313612) = T
0.042857(1581.121109) = T
67.76210738 = T
67.8 N = T

Did I have the equations right??
 
Last edited:
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Your calculation of v looks weird, but the general concept (and the result) are fine.
 

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