What exactly allows a differential relation form of an equation?

Click For Summary
SUMMARY

The discussion centers on the transition from the equation y = fθ to its differential relation form dθ/dy = 1/f, specifically within the context of optics in Stellar Astrophysics. The small-angle approximation, tan(θ) ≈ θ, is crucial in deriving this relationship. The key insight is that the differential form can be obtained through differentiation, where dy = f dθ, allowing for the manipulation of variables under certain conditions. Understanding these transitions is essential for grasping the underlying principles of differential relations in physics.

PREREQUISITES
  • Understanding of calculus, specifically differentiation.
  • Familiarity with the small-angle approximation in trigonometry.
  • Basic knowledge of optics and its mathematical representations.
  • Concept of differential relations in physics.
NEXT STEPS
  • Study the principles of differentiation in calculus.
  • Explore the small-angle approximation and its applications in physics.
  • Learn about differential equations and their significance in modeling physical phenomena.
  • Investigate the mathematical foundations of optics, particularly in Stellar Astrophysics.
USEFUL FOR

Students and professionals in physics, particularly those focusing on optics and astrophysics, as well as anyone interested in the mathematical foundations of differential relations.

rexregisanimi
Messages
42
Reaction score
6
What exactly allows a "differential relation" form of an equation?

I understand this in a superficial way but I'd really like some more clarification. If anybody can provide a little better understanding on this subject, please feel free to post anything at all. Even a sentence or two would be helpful.

I am reading through the optics section of my Stellar Astrophysics book and I came across the following sentences:

Using the small-angle approximation, tan(θ) ≈ θ, for θ expressed in radians, we find

y = fθ.​

This immediately leads to the differential relation known as the plate scale, dθ/dy,

[itex]\frac{dθ}{dy}[/itex] = [itex]\frac{1}{f}[/itex].​

What I don't completely understand is how and why one can simply go from the y=fθ form to the dθ/dy = 1/f form. I understand what the equation means but I don't understand the rules behind switching from one form to the other. Are there any or can I change any two variables to differential form to get a new relation? Any help or guidance at all would be appreciated.
 
Physics news on Phys.org


For f not a function of y or theta,

dy= fdθ

Then its just symbol pushing.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K