What force do ropes exert on a sign

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The discussion focuses on calculating the forces exerted by two ropes on a sign weighing 648 N, suspended at an angle of 38 degrees with the horizontal. The key equations used include the equilibrium condition A + B + W = 0 and the components of forces Fh = F cos x and Fv = F sin x. The solution reveals that each rope exerts a vertical force of 324 N, derived from the vertical components of the tension forces. The tension in the ropes, denoted as A and B, is equal, leading to the conclusion that A = B = 324 N/sin(38°).

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Homework Statement


A sign that weights 648 N is suspended by two ropes that make an angle of 38o with the horizontal. What force does each rope exert on the sign?


Homework Equations


A + B + W= 0
Fh= F cos x
Fv= F sin x


The Attempt at a Solution


This is how my textbook says to do it:

The direction of W is down, so the direction of A + B is up. The sum A+B has no horizontal components, so the horizontal components of A and B, Ah and Bh have equal magnitudes. Now, Ah = Acos38o and Bh=Bcos38o. Since Ah=Bh, the magnitudes of A and B must be equal. The magnitude of the sum of the vertical components of A and B equals the magnitude of the weight of the sign, 648 N. That is, Av + Bv =648 N Since Av = Asin38 and Bv = Bsin38 and A=B, Av=Bv.
Thus,
Av=Bv =1/2(648N)= 324N
And.. A=Av/sin38 = x
B=A= x

They don't tell me what x should be, nor what the 324N is for. Please help
 
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ahrog said:

Homework Statement


A sign that weights 648 N is suspended by two ropes that make an angle of 38o with the horizontal. What force does each rope exert on the sign?


Homework Equations


A + B + W= 0
Fh= F cos x
Fv= F sin x


The Attempt at a Solution


This is how my textbook says to do it:

The direction of W is down, so the direction of A + B is up. The sum A+B has no horizontal components, so the horizontal components of A and B, Ah and Bh have equal magnitudes. Now, Ah = Acos38o and Bh=Bcos38o. Since Ah=Bh, the magnitudes of A and B must be equal. The magnitude of the sum of the vertical components of A and B equals the magnitude of the weight of the sign, 648 N. That is, Av + Bv =648 N Since Av = Asin38 and Bv = Bsin38 and A=B, Av=Bv.
Thus,
Av=Bv =1/2(648N)= 324N
And.. A=Av/sin38 = x
B=A= x

They don't tell me what x should be, nor what the 324N is for. Please help

Start by drawing a free body diagram (FBD). Then uses Newton's second law (Fnet = ma) in both the x and y directions. You'll end up with two equations that you can solve simultaneously.

HINT: The force that the ropes exert on the sign is equal to the tension in the ropes.

CS
 

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