What Force is Needed for 1.5 m/s² Acceleration in the +y Direction?

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SUMMARY

The discussion focuses on calculating the additional force required for an object with a mass of 2.5 kg to achieve an acceleration of 1.5 m/s² in the +y direction. Two forces are acting on the object: F1 with a magnitude of 0.50 N in the +x direction and F2 at a 45-degree angle with a magnitude of 2.0 N. The net force equation Fnet = F1 + F2 + F3 is utilized, leading to the conclusion that the additional force FX required is 26.84 N in the +x direction. The confusion arises from discrepancies between the calculated force and the book's answer of (0.91 N)i + (2.3 N)j.

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Homework Statement


Two forces act on an object of mass 2.5kg; force F1 that is directed alont the +x-direction and has magnitude of .50N and force F2 that points at a 45 degree angle in the +y and -x quadrant and has magnitude 2.0N. Find the additional force, if any such that the object will accelerate in the +y direction with magnitude 1.5m/s/s.

Homework Equations


F=ma
Fnet=F1+F2+F3+etc...
F=Fsin[tex]\theta[/tex]

The Attempt at a Solution


Fnety= F2sin[tex]\theta[/tex]+FX-Fg

FX= missing force= ?
Fnety= (2.5kg)(1.5m/s/s)= 3.75N
F2sin[tex]\theta[/tex]= 1.414N
Fg= 2.5*9.8=24.5N

3.75 = FX + 1.414 -24.5
FX= 26.84N

I'm not sure if I'm even trying to go about the problem correctly.

The selected answers in the back of the book has the answer as:
(0.91N)i+(2.3N)j

so I'm really confused.
 
Physics news on Phys.org
Let the third force be xi + yj.
Take x and y components of all the three forces. Since the resultant force is along y axis, total x-component must be zero.
Hence total y component must be equal to ...?
 

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