What forces do flanged bushes on a door hinge experience?

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Discussion Overview

The discussion revolves around the forces experienced by flanged bushes in door hinges, specifically in the context of a door weighing 100 kg. Participants explore the distribution of forces on the hinges due to the weight of the door and its center of mass, as well as the moments created by the door's geometry.

Discussion Character

  • Technical explanation, Debate/contested

Main Points Raised

  • One participant proposes that each flange will see a force of 500 N due to the weight of the door, suggesting that the flanges experience the mass directly.
  • Another participant mentions that in practical scenarios, such as hanging a field gate, it is difficult to achieve equal load distribution between hinges, as one may "bottom out" first.
  • A different participant explains that only one hinge will experience a vertical shear force, while the upper hinge will have an outward force and the lower hinge an inward force, leading to a proposed horizontal force distribution of +500 N and -500 N.
  • This same participant also notes that without resilient hinge mountings or fine adjustments, it is uncertain which hinge will bear the additional vertical load of 1000 N.

Areas of Agreement / Disagreement

Participants express differing views on the load distribution between the hinges, with some suggesting equal sharing of forces while others highlight practical limitations that may lead to uneven load distribution.

Contextual Notes

Assumptions about hinge resilience and adjustment mechanisms are not fully explored, and the discussion does not resolve the exact forces on each hinge under varying conditions.

ghobbs
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Hi. I have a door mounted on 2 hinges, aligned on a vertical axis. The hinge shafts run in flanged plain bushes.

I'm trying to work out what forces the flanged bushes will see. The door weighs 100Kg, with the centre of mass at the centre of the door. The door is 2m wide and 2m vertically between hinges.

I think that the flanges will see the mass of the door, i.e. each flange sees 500N.

The bushes will also see radial forces, counteracting the moment of the door about the hinges. Based on the moment and geometry, will the top bush see 1000N and the lower bush -1000N?
 
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my experience is limited to hanging a field gate. In that case its impossible to get both hinges to share the load because they are never the same distance apart. One or the other "bottoms out" first and carries the vertical load.
 
As CW wrote, only one of the hinges will have a shear / vertical force on it but the upper hinge will have a force outwards and the lower will have a force inwards. This simple setup gives the horizontal forces as + and - 500N, assuming the cm of the door is half way between the levels of the hinges the total moment being 1000Nm and each hinge provides half the necessary torque against this( 500+500, one way = 1000 the other way). Unless you have some resilience in the hinge mountings plus some way of fine adjustment of the vertical height of the hinges, you can't be sure which hinge will take all the additional vertical load of 1000N.
 
Ah yes, I understand now. Thanks for the clarification.
 

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