What formula creates the exponential curve in Boltzmann distribution figure 2a?

[rabbed]

TL;DR

Boltzmann distribution

Hello

Can anyone explain what formula (or parameters) was used to create the exponential Boltzmann distribution in fig 2a of this document?
http://image.sciencenet.cn/olddata/kexue.com.cn/upload/blog/file/2009/5/20095251352697121.pdf

I figure it must be something like y=e^(ln(600)-b*x) for some b?

 

[mjc123]

Doesn't the caption explain it?

 

[rabbed]

funny,
But what values to put in?
Around x=1 it seems to get y=200
e^(ln(600)-1/(1.381×10^-23*300)) = 0?

 

[phyzguy]

Since the x-axis is βε, the only free parameter is α. As you realized, it goes through ~600 at βε=0, so the formula being plotted is clearly 600*exp(-βε). Or, if you like, exp(log(600) - βε)

 

[rabbed]

Doh! So simple, thanks!