What fraction of light do these glasses transmit

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Discussion Overview

The discussion centers around the logarithmic scale used by welders to determine the shade number of protective eyewear based on the fraction of visible light transmitted by the glass. Participants explore the implications of this scale for specific values of light transmission, particularly in relation to welding and viewing a solar eclipse.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • Some participants present the equation for shade number n as n = 1 − 7log(T)/3, where T is the fraction of light transmitted.
  • One participant calculates the shade number for a transmission of ⅛, stating T = 1/8 and asking for arithmetic confirmation.
  • Another participant sets up the equation for shade number 14, rearranging it to solve for T and inquires about reversing the logarithm to find the fraction of light transmitted.

Areas of Agreement / Disagreement

Participants appear to agree on the form of the equation used for calculating shade numbers, but there is no consensus on the calculations or the specific values of T for the welding glasses discussed.

Contextual Notes

The discussion includes unresolved mathematical steps and assumptions regarding the logarithmic function and its application in determining light transmission.

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Welders use a logarithmic scale to identify protective eyewear. The shade number n, is given by the
equation n = 1 − 7logT/3 , where T is the fraction of visible light that glass transmits.

a. What shade number should a welder use that only transmits ⅛ of the light entering the glass?
b Viewing a solar eclipse through #14 welding glasses is considered safe. What fraction of light do
these glasses transmit.
 
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fxacx said:
Welders use a logarithmic scale to identify protective eyewear. The shade number n, is given by the
equation n = 1 − 7logT/3 , where T is the fraction of visible light that glass transmits.

a. What shade number should a welder use that only transmits ⅛ of the light entering the glass?
b Viewing a solar eclipse through #14 welding glasses is considered safe. What fraction of light do
these glasses transmit.

is the equation $n=1-7\log \left(\dfrac{T}{3}\right)$ ... ?

please confirm
 

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fxacx said:
Welders use a logarithmic scale to identify protective eyewear. The shade number n, is given by the
equation n = 1 − (7log(T))/3 , where T is the fraction of visible light that glass transmits.

a. What shade number should a welder use that only transmits ⅛ of the light entering the glass?
So T= 1/8. n= 1- (7 log(1/8))/3. Can you do the arithmetic?

b. Viewing a solar eclipse through #14 welding glasses is considered safe. What fraction of light do these glasses transmit.
Now n= 14 so 14= 1- (7 log(T))/3. 14- 1= 13= -(7/3) log(T).
-(3/7)(13)= -39/7= log(T). Do you know how to "reverse" log?
 
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