What Gauge Pressure is Needed for a Water Jet to Reach 29.8 m/s?

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SUMMARY

The discussion centers on calculating the gauge air pressure required in a fire extinguisher to achieve a water jet speed of 29.8 m/s, with the water level 0.515 m below the nozzle. Participants utilized Bernoulli's equation, specifically the form: p1 + 1/2 * ρ * v1² + ρ * g * y1 = p2 + 1/2 * ρ * v2² + ρ * g * y2. The initial attempt to solve for p2 resulted in an incorrect value of -4.49 x 10^5 Pa, indicating a misunderstanding of the variables, particularly the height terms in relation to the nozzle position.

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Help! Physics Fluids problem

Homework Statement


Water is forced out of a fire extinguisher by air pressure. How much gauge air pressure in the tank (above atmospheric) is required for the water jet to have a speed of 29.8 m/s when the water level is d=0.515 m below the nozzle?


Homework Equations


I tried using bernoulli's equation, p1+ 1/2*p*v1^2 + p*g*y1= p2 + 1/2*p*v2^2 + p*g*y2
I am not sure what variables I am supposed to put in where, as the diagram i am given in the question is that of a tank with a water pipe in the middle of it.


The Attempt at a Solution


I attempted to solve for p2, using p1 as atmospheric pressure, density as the density of water, v1 as 29.8m/s^2, height as 0.515. The rest of the terms on the second half of the equation I thought would cancel because the height would be 0 and I thought the starting velocity is 0. I ended up getting -4.49 x 10^5 Pa...which isn't right...please help!
 
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The height of the water in the jet is below the nozzle. I think you want to either make y1 negative, or make it zero and use the .515m for y2.
 

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