# What happened to Force in this equation?

1. Sep 27, 2009

### laxboi33

1. The problem statement, all variables and given/known data

a 2000 kg car, after its brakes are locked up, skids and comes to a rest. The coefficient of kinetic friction between rubber and pavement is 0.8. Find deceleration of the car.

2. Relevant equations

M= 2000 kg
W= mg
V= 0

3. The attempt at a solution

N= mg = 2000 x 9.8 = 19600 N

Fk = N * Mk = 16000

F = ma

-Fk = 2000 a .......Where did F go? In most cases I thought F-Fk = ma. Here the F is missing. Is it because the car is skidding? I'm not sure and I was wondering if you guys could help me out.

2. Sep 27, 2009

### rock.freak667

F-Fk=ma gives the resultant force.

Fk causes the car to decelerate so if we use ma=Fk, 'a' gives the deceleration of the car.

3. Sep 27, 2009

### RoyalCat

Newton's Second Law:

$$\Sigma \vec F = m\vec a$$

The sum of all forces is equal to the mass of the object times its acceleration.
For there to be a sum of forces, there doesn't have to be more than one force!

In this case, the only force acting on the car in the horizontal direction is the force of the kinetic friction, so:
$$\vec f_k = m\vec a$$

The friction force in this case isn't a reaction force to an external force applied to the object, but it is present because there is relative motion between the car and the surface it is on.