I What happens to X-rays if they do not meet Bragg's law?

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Bragg's law, expressed as 2d sin(θ) = mλ, dictates the conditions for diffraction in crystal planes. If an X-ray of slightly different energy strikes the crystal at the same angle θ, it will not produce the same diffraction pattern due to the change in wavelength. However, the electrons in the crystal continue to vibrate, allowing the possibility of diffraction at different angles for the new wavelength. The energy from the X-ray does not spread evenly in 4π but can interact with other crystal planes. Each wavelength generates its own distinct diffraction pattern, which can overlap on a detection screen.
gaiussheh
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Bragg's law states that it must meet ##2d\sin[\theta]=m\lambda## for diffraction to happen. I just wonder, if you have an x-ray of slightly different energy that hits the crystal plane at the same angle ##\theta##, what would happen? It certainly can't form the same diffraction pattern at the same angle ##\theta##, but as the electrons in the crystal still vibrate, the x-ray still goes somewhere. Can they find another plane so that the diffraction happens at another angle? Or is the energy spread out evenly in ##4\pi##?
 
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For any EM radiation, each wavelength forms its own diffraction pattern independently and these are superimposed on a screen.
 
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