What height will your cousin reach if thrown at 5 m/s?

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SUMMARY

The maximum height reached by an object thrown vertically at an initial velocity of 5 m/s is calculated to be 1.3 meters. This conclusion is derived using the kinematic equation d = (Vi * T) + (0.5 * A * T^2), where Vi is the initial velocity, A is the acceleration due to gravity (-9.8 m/s²), and T is the time of flight (0.51 seconds). The calculations confirm that the height achieved is indeed 1.3 meters, validating the solution presented in the discussion.

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Homework Statement



If you toss your little cousin straight up into the air at 5 m/s, how high above your hands will he/she go?


0.5 m

1.3 m

2.0 m

70 m


Homework Equations



d = (0-5^2) / 2 (-9.8)
d = 1.3 m

The Attempt at a Solution



My cousin will fly 1.3 m high if I throw her at 5 m/s.

Is that correct?
 
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Distance = ??
Tine = ??
Velocity initial=5m/s
Velocity final = 0m/s
Acceleration = -9.8m/s

T = Vf-Vi / A
T = -5 / -9.8
T = .51s

D = ViT + AT^2 / 2
D = (5)(.51) + ((-9.8)(.51)(.51) / 2)
D = 1.3

yes 1.3 is correct
 

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