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Find the length of the parametrized curve given by

x(t) =[tex]t^{2}-8t + 24[/tex]

y(t) =[tex]t^{2}-8t -7 [/tex]

How many units of distance are covered by the point P(t) =(x(t), y(t)) between t=0, and t =8?

So my first step of course is to find dx/dt and dy/dt

[tex]\frac{dx}{dt}=2t-8[/tex]

[tex]\frac{dy}{dt}=2t-8[/tex]

Then set up the arc length equation

arc length = [tex]\int^{8}_{0}\sqrt{{\frac{dx}{dt}}^2+{\frac{dy}{dt}}^2}dt[/tex]

= [tex]\int^{8}_{0}\sqrt{{(2t-8)}^2+{(2t-8)}^2}dt[/tex]

= [tex]\int^{8}_{0}\sqrt{2{(2t-8)}^2}dt[/tex]

= [tex]\int^{8}_{0}\sqrt{2}(2t-8)dt[/tex]

=[tex]\sqrt{2}\int^{8}_{0}(2t-8)dt[/tex]

=[tex]\sqrt{2}\left[{t}^2-8t\right]^{8}_{0}dt[/tex]

Which give me an answer of zero when the answer is suppose to be 45.2548.

What I am doing wrong? Thanks.