What Initial Pressure and Volume Are Required to Fire a Pellet at 100 m/s?

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SUMMARY

The discussion focuses on determining the initial pressure and volume required to fire a spherical pellet with a radius of 8.75 mm at a velocity of 100 m/s, necessitating 1.75 J of work. Using the adiabatic expansion equation, the initial pressure (P1) was calculated to be 420,465 Pa, and the initial volume (V1) was found to be 10^-5 m³. The final volume (V2) was computed as 2.79 x 10^-5 m³, leading to a barrel length of 0.0744 m. The goal is to find values that satisfy the work criteria while maintaining a manageable initial volume for multiple shots.

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  • Understanding of adiabatic processes and equations
  • Familiarity with the ideal gas law and pressure-volume relationships
  • Basic knowledge of work-energy principles in physics
  • Ability to perform iterative calculations for pressure and volume
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  • Study the principles of adiabatic expansion in thermodynamics
  • Learn about the ideal gas law and its applications in pressure-volume calculations
  • Explore iterative numerical methods for solving equations
  • Investigate the design considerations for pneumatic systems and barrel lengths
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This discussion is beneficial for physics students, engineers working with pneumatic systems, and hobbyists interested in projectile motion and gas dynamics.

RazerM
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Homework Statement


1.75 J is required to fire a spherical pellet of radius 8.75 mm at a maximum velocity of 100 m/s

Find appropriate values for the inital pressure and volume and final pressure and volume


Homework Equations


Adiabatic Expansion
P_{1}V_{1}^{\gamma}=P_{2}V_{2}^{\gamma}

\gamma=1.40\qquad P_{2}=10^5\text{ Pa}

W_{\text{total}}=\frac{P_{1}V_{1}-P_{2}V_{2}}{\gamma-1}

<br /> \begin{align*}<br /> W_{\text{total}} &amp;= W_{\text{atm}}-W_{\text{useful}} \\ \frac{P_{1}V_{1}-P_{2}V_{2}}{\gamma-1}&amp;=10^{5}(V_{2}-V_{1})-1.75<br /> \end{align*}<br />

The Attempt at a Solution


<br /> \begin{align*}<br /> V_{2}&amp;=V_{1}\left( \frac{P_{1}}{P_{2}} \right)^{\frac{1}{\gamma}}\\<br /> V_{2}&amp;=V_{1}\left( \frac{P_{1}}{10^{5}} \right)^{\frac{1}{1.4}}\\<br /> \end{align*}<br />
It is then possible to rearrange work equation into
V_{1}\left( [P_{1}+4\cdot 10^{4}]-\left[ 1.4\cdot 10^{5}\left( \frac{P_{1}}{10^{5}} \right)^{\frac{1}{1.4}} \right] \right)=0.7

\text{Then using an arbitary guess for }V_{1}\text{ and an iterative process to find }P_{1}\text{ I found }
<br /> V_{1} = 10^{-5}\text{ m}^{3}
<br /> P_{1} = 420465\text{ Pa}
<br /> V_{2} = 2.79\cdot 10^{-5}\text{ m}^{3}<br />
Giving a ridiculous barrel length of
<br /> \begin{align*}<br /> L &amp;= \frac{V_{2}-V{1}}{\pi r^{2}} \\<br /> L &amp;= 0.0744\text{ m}<br /> \end{align*}<br />


I'm not asking for a full solution; just a hint as to how to find out values that satify the criteria of work and have a reasonably small V_1 so that there can be many shots for say a 0.001m^3 tank
 
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The pellet travels down a cylindrical barrel of length L whose cross-sectional area is A = \pi r^2 where r = 8.75 mm. So the final volume is LA. The minimum final pressure is 1 atm. Choose a reasonable length for the barrel, say .75 m. Find an initial volume and pressure such that the work done in adiabatically expanding to volume LA is equal to 1.75 J.

AM
 
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