What input work is required for this machine

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SUMMARY

A machine with 25% efficiency performing 200 J of external work requires an input work of 800 J. This conclusion is derived from the efficiency formula, which states that efficiency equals output work divided by input work. Therefore, to find the input work, the calculation is 200 J divided by 0.25, resulting in 800 J.

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hisbul
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Homework Statement


a 25% efficient machine performs external work of 200 J. what input work is required?..please answer,,is the answer is 800 J?



Homework Equations





The Attempt at a Solution


800 J
 
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welcome to pf!

hi hisbul! welcome to pf! :smile:
hisbul said:
a 25% efficient machine performs external work of 200 J. what input work is required?..please answer,,is the answer is 800 J?

yup! :biggrin:
 

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