What is 3-Digit Floating Point Arithmetic and How Does It Function?

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Discussion Overview

The discussion revolves around the concept of 3-digit floating point arithmetic, exploring its definition, implications, and context within mathematical operations, particularly in relation to catastrophic cancellation in the quadratic equation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question whether 3-digit arithmetic refers to three decimal places, three significant figures, or base 3 arithmetic.
  • One participant suggests that 3-digit arithmetic implies the ability to perform operations with numbers ranging from 100 to 999.
  • Another participant clarifies that the context involves floating point numbers and catastrophic cancellation, specifically mentioning the rounding of inputs and outputs to three digits.
  • There is a discussion about whether all numbers in the calculation process need to be rounded to three decimals at each step or only the final result.
  • One participant argues that there is no difference between using three digits from the outset and rounding to three digits, while another participant contests this view.
  • A later reply proposes that in floating point arithmetic, numbers are represented by a 3-digit mantissa and an exponent, providing examples of how specific numbers would be represented.

Areas of Agreement / Disagreement

Participants express differing views on the definition and implications of 3-digit arithmetic, with no consensus reached on whether it refers to initial digit limits or rounding practices.

Contextual Notes

There are unresolved questions regarding the specific requirements for rounding during calculations and the implications of using three digits versus rounding to three digits.

brandy
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what is 3(or i, where i=1,2,3,4...∞) digit arithmetic? is it just working with 3 decimals or 3 significant figures? or is it base 3 arithmetic?
 
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brandy said:
what is 3(or i, where i=1,2,3,4...∞) digit arithmetic? is it just working with 3 decimals or 3 significant figures? or is it base 3 arithmetic?

Context?

The expression could mean anything.

But if I heard someone say they could do 3 digit arithmetic, I would assume they could add subtract and multiply 3-digit numbers (100-999).
 
the context was talking about floating point numbers and catastrophic cancellation in the quadratic equation.

it said using 3 digit arithmetic:
*subs in some numbers, 0.2, 100.9 etc into the quad equation and at the end rounds the entire number to 3 digits*

am i right in assuming that all the numbers used to input had to be 3 decimals and then the final number had to be 3 digits?
or does every number in the process have to be rounded to 3 decimals as the number is created? step by step?
 
Of course, any decent calculator or computer will carry 12 or more digits for its calculations. But just to give a simple example, that a human could calculate easily, of how cancellation happens, they are restricting to three digits. I don't see any difference between using three digits from the outset and rounding to three digits.
 
HallsofIvy said:
I don't see any difference between using three digits from the outset and rounding to three digits.
What? Of course there's a difference.
 
Since the context is floating point arithmetic, my guess at what you're asking is that numbers are represented by a 3-digit mantissa and an exponent.

Using the numbers you gave as examples, 0.2 would be 2.00 x 10-1 and 100.9 would be 1.01 x 102.

If you want a better answer, you'll need to ask a question that is clearer.
 

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