What is a fColumb? Finding Net Electric potential, still wrong

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The discussion centers on calculating the net electric potential at point P due to four particles, with a charge of 5.50 fC and a distance of 3.00 cm. The user initially miscalculated the potential by not converting femtocoulombs (fC) to coulombs, which is essential for accurate results. They corrected their approach by recognizing that the negative charge is 2d away from point P instead of d. After adjusting their calculations, they found a potential of 6.37E-10 V. The prefix "f" in fC stands for femto, indicating a factor of 10^-15.
mr_coffee
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I'm suppose to find the net electric potential at point P due to the four particles, if V = 0 at infinity, q = 5.50 fC, and d = 3.00cm?
THe picture is here: http://www.webassign.net/hrw/hrw7_24-33.gif
I used V = (5.50/.03 + 5.50/.03 - 5.50/.03 - 5.50/(.06));
I noticed that the very end negative charge is 2d away from P not just d. But i only have 2 more chances left to get it right. so i found V = 6.37E-10 V. But I never converted 5.50 fC to just C. So I'm assuming my answer is off slightly, anyone know what fC stands for also, do yuou know if I'm right? Thanks!]
 
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The potential at a distance r from a point charge is k q/r. The prefix "f" stands for femto, which means 10^{-15}.
 
awesome, thanks guys, it worked great!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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