What is a limit of a sequence?

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for lim n to infinity {2 [(-1)^n] },what should i write either converges or diverges because it tends to be -2 or +2
 
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If I'm not mistaken, first thing you need to check in a series if the limit is unique , as in when the series limit is one number.
then you should check if that limit is zero or not , then you can apply usual methodes know to find out.
So in your case it diverge.
 
is it if there is (-1^n) and n limit to infinity means always diverges??
 
doesn't have to.
[(-1)^n]/n have a limit when n tends to be infinite 0 , this series converge.
I sense you don't know much about limits , maybe you didn't studied well that chapter.
it's fairly easy to know them.
 
"limit" is how a function's behavior changes when its argument(or variable) gets close to a certain value(or a point)
 
but ur question simply says
arildno :
What is the definition of a limit?

u dint specify it was limit to a sequence...
 
i just thought u were saying abt limit of a function...so sorry
 
teng125 said:
for lim n to infinity {2 [(-1)^n] },what should i write either converges or diverges because it tends to be -2 or +2

OK, the lim inf is -2 and the lim sup is +2, and thus the lim is...
 
teng:
Forget subsequences, lim infs and all that.
Those concepts won't help you a bit, because you betray an uncertainness abut the very concept of a limit in the first place.

Let us take a typical textbook definition:
"We say that a number L is a LIMIT of a sequence [itex]a_{n}[/tex] if for any [itex]\epsilon>0[/itex] there exists a number N, so that for any n>N, [itex]|a_{n}-L|<\epsilon[/itex]"<br /> Furthermore, a sequence is said to diverge if no such number L exists.<br /> <br /> 1. The first thing to note is that L (if it exists) is a NUMBER, and only that.<br /> It is not a hand-wavy action by which we describe the function's behaviour. It is a number. Period.<br /> <br /> 2. Secondly, the definition should be regarded as a recipe of detemining whether or not an arbitrarily chosen L is a limit to the sequence or not.<br /> <br /> 3. Let us for convenience sake pick L=2 first, and check whether it can be said to be a limit to the sequence:<br /> <br /> Consider the absolute valued difference: [tex]|2(-1)^{n}-2|[/tex]<br /> Now, when n is even, this difference equals 0, but when n is odd, the difference equals 4.<br /> Thus, by picking [itex]\epsilon<4[/itex], and remembering that odd numbers can be arbitrarily big, we see that there cannot exist a number N so that for ANY n>N, the difference is less than [itex]\epsilon[/itex]<br /> <br /> Thus, 2 cannot be regarded as a limit L to our sequence.<br /> <br /> <br /> Do you think -2 can be a limit?<br /> What about any other number?<br /> Answer those questions, and you have the answer to your own question.[/itex]