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What is Channel Number? (In gamma spectroscopy)

  1. Oct 25, 2013 #1
    Really quick question.

    In a graph like this:
    http://en.wikipedia.org/wiki/File:Cs137_Spectrum.PNG

    Source

    What does the Channel Number represent?

    Also, just to make sure, am I right in saying the count rate is [itex]\frac{\delta m}{\delta t}[/itex] ?
    where m is the cumulative number of scintillations
    and t is time

    Edit: I've just noticed the graph says "number of counts" and not "count rate". Some graphs do though, so can I change my second question to: Is a count a single scintillation?
     
  2. jcsd
  3. Oct 25, 2013 #2

    Astronuc

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    Staff: Mentor

    Channel number is a band of energy (ΔE). There is a total energy, and one divides that into a number of channels.

    A count is one (detection) event or scintillation. The systems captures the counts, and the count rate is simply the difference in accumulated counts divided by the counting interval.
     
  4. Oct 26, 2013 #3
    Thanks Astronuc. So the scintillation detectors are sensitive to the energy of the flash, but why do we divide this into discrete energy bands instead of just having energy on the horizontal axis?
     
  5. Oct 26, 2013 #4

    jtbell

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    Have you ever used histograms before? How else would you plot a set of e.g. 10000 experimentally-measured energy values in a way that shows how they are distributed versus energy?

    After you've made a histogram of your data, then you can find a smooth curve that at least approximately "fits" the data, and plot that curve along an energy-axis that doesn't have "bins" or "channels", but that's a somewhat different beast.
     
  6. Oct 26, 2013 #5

    Astronuc

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  7. Oct 27, 2013 #6
    jtbell, ah yeah of course. Sorry I didn't think before posting that question.
     
  8. Oct 27, 2013 #7

    mfb

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    Make a Gaussian distribution out of every measured value, add them up.
    It is possible to plot data without histogram bins, it is just impractical in many cases. Unbinned fits use very similar methods.
     
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