MHB What is Jacobi's identity for Lie derivatives on a smooth manifold?

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Jacobi's identity for Lie derivatives states that for any vector fields X, Y, and Z on a smooth manifold, the equation [L_X, [L_Y, L_Z]] + [L_Y, [L_Z, L_X]] + [L_Z, [L_X, L_Y]] = 0 holds true. This identity is a fundamental property of Lie brackets and reflects the antisymmetry and bilinearity of the Lie derivative operation. The problem posed in the thread remains unanswered, prompting the author to share their own solution. The discussion emphasizes the importance of understanding the implications of Jacobi's identity in the context of differential geometry. Engaging with this identity is crucial for deeper insights into the structure of vector fields on manifolds.
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Here is this week's POTW:

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Prove that for all vector fields $X$, $Y$, and $Z$ on a smooth manifold, their Lie derivatives $\mathscr{L}_X$, $\mathscr{L}_Y$, and $\mathscr{L}_Z$ satisfies Jacobi’s identity $$[\mathscr{L}_X,[\mathscr{L}_Y,\mathscr{L}_Z]] + [\mathscr{L}_Y, [\mathscr{L}_Z,\mathscr{L}_X]] + [\mathscr{L}_Z, [\mathscr{L}_X, \mathscr{L}_Y]] = 0$$

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No one answered this week's problem. You can read my solution below.
Let $X, Y, Z$ be vector fields on a smooth manifold $M$. They satisfy Jacobi's identity $[[X,Y], Z] + [[Y,Z],X] + [[Z,X],Y] = 0$, so $\mathscr{L}_{[[X,Y],Z]} + \mathscr{L}_{[[Y,Z],X]} + \mathscr{L}_{[[Z,X],Y]}.$ Therefore

$$[[\mathscr{L}_X,\mathscr{L}_Y], \mathscr{L}_Z] + [[\mathscr{L}_Y,\mathscr{L}_Z],\mathscr{L}_X] + [[\mathscr{L}_Z,\mathscr{L}_X], \mathscr{L}_Y]$$
$$=[\mathscr{L}_{[X,Y]},\mathscr{L}_Z] + [\mathscr{L}_{[Y,Z]}, \mathscr{L}_X] + [\mathscr{L}_{[Z,X]},\mathscr{L}_Y]$$
$$=\mathscr{L}_{[[X,Y],Z]} + \mathscr{L}_{[[Y,Z],X]} + \mathscr{L}_{[[Z,X],Y]}$$
$$= 0$$