What is Liouville's theorem all about - Thermodynamics

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Homework Help Overview

The discussion revolves around Liouville's theorem in the context of thermodynamics, specifically relating to the behavior of an ideal gas undergoing adiabatic free expansion. Participants are exploring the implications of the theorem on microstates and macrostates during this process.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to reconcile the implications of Liouville's theorem with the behavior of an ideal gas during free expansion, questioning how microstates are affected by changes in volume. Some are exploring definitions of microstates and the relationship between macrostates and volume changes.

Discussion Status

The discussion is active, with participants raising questions about the validity of Liouville's theorem in irreversible processes and the relationship between microstates and macrostates. Some guidance has been offered regarding the need for reversible paths in the context of Liouville's theorem.

Contextual Notes

There is an ongoing exploration of the definitions and implications of microstates and macrostates, particularly in relation to the constraints of irreversible processes and the assumptions underlying the application of Liouville's theorem.

annetjelie
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I'm having difficulties understanding what liouville's theorem is all about. I was "meditating" over an adiabatic free expansion and i got stuck because of a contradiction in my reasoning so it seems i still don't have a clue what liouville actually wants me to understand :)

So imagine an ideal gas in volume V that adiabatically expands (free) to a volume 2V. This means more microstates.

Then my contradiction: liouville says that the volume of the microstates (of the macrostate) in phase space under hamiltonian flow stays the same. And as the energy of an ideal gas after free expansion also remains the same, this would mean that the volume of the microstates corresponding to the first macrostate would stay the same
So i get the same "amount" of microstates for the final macrostate which is in contradiction with the above statement and is just plain wrong

Clearly there's a fundamental flaw in my reasoning, and it would mean a lot if someone could give me a nudge in the right direction! Thanks!

*edit* okay i meditated a little more and i guess it's because you have to find a reversible path between the initial and final state because it's an irreversible process, so you can't use Q=0 (and then E won't be constant). Is this right?
 
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So imagine an ideal gas in volume V that adiabatically expands (free) to a volume 2V. This means more microstates.

If the number of gas atoms/molecules N is contant, why would the number of microstates increase?

What is the definition of microstate.
 
Doesn't the number of macrostates increase because V increases?
 
arnesmeets said:
Doesn't the number of macrostates increase because V increases?
that's what i thought. If you expand a gas to a volume twice its initial volume than the phase space of that gas will enlarge by a factor 2^N with N the number of particles, and so there are more possible microstates. No??
 


Your doubt is correct. Liouville theorem does not hold for irreversible process, like adiabatic expansion. Because the phase space is not conserved, as you know, the entropy change is positive.
 

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