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What is ripple factor in halfwave rectifier?

  1. May 15, 2012 #1
    Well rms current in AC is I / √2 and average current in DC is I /π ( in half wave)

    ripple factor is rms current in AC divided by average current in DC which according to me is 2.2. But value given is 1.21 everywhere

    Is my formula wrong. Have i misunderstood ripple factor?
     
  2. jcsd
  3. May 16, 2012 #2

    Philip Wood

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    Gold Member

    This is, imo, quite a tricky little calculation. Thumbnail solution attached.
     

    Attached Files:

    Last edited: May 16, 2012
  4. May 16, 2012 #3
    Ok thank you
     
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