What is ripple factor in halfwave rectifier?

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jd12345
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Well rms current in AC is I / √2 and average current in DC is I /π ( in half wave)

ripple factor is rms current in AC divided by average current in DC which according to me is 2.2. But value given is 1.21 everywhere

Is my formula wrong. Have i misunderstood ripple factor?
 
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This is, imo, quite a tricky little calculation. Thumbnail solution attached.
 

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