Formula for ripple factor in filter circuits

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SUMMARY

The discussion centers on two formulas for calculating ripple factor in filter circuits: r = (Vrpp/Vdc) and r = (Vrms/Vdc). The first formula, commonly used in basic electronics and referenced by Floyd, utilizes peak-to-peak voltage (Vrpp), while the second, from Boylestad's work, employs root mean square voltage (Vrms). It is established that these formulas are not equivalent due to the non-sinusoidal nature of the waveform, making the peak-to-peak method more straightforward for practical applications.

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  • Basic principles of waveform analysis
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iampaul
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i have come across two different formulas for ripple factor:
One is r= (Vrpp/Vdc), where Vdc is the dc voltage of the output and Vrpp is the peak to peak ripple voltage. My professor uses this formula and I have also seen it being used in basic electronics by Floyd
Another one is r= Vrms/Vdc from electronics by boylestad. Are these correct?

Is it possible to show that they are equivalent. Please help. Thanks in advance
 
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They are not equivalent but Wikipedia shows them both as being used.

http://en.wikipedia.org/wiki/Ripple_(electrical)

So, it depends on your definition.

Peak to peak is easier to use and RMS would be difficult because the waveform is not sinusoidal.
 
Thanks for the reply.
 

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