What is [s]motion[/s] moment of inertia of an equilateral triangle?

AI Thread Summary
The discussion focuses on calculating the moment of inertia for an equilateral triangle, specifically for a thin lamina. Participants suggest using the integral definition of moment of inertia, I = ∫ r² dm, and recommend drawing the triangle to facilitate the calculation. The conversation also clarifies the terminology, questioning the phrase "motion of inertia" and distinguishing between the second moment of area and mass moment of inertia. Ultimately, the emphasis is on determining the specific type of moment of inertia the inquirer is interested in. The thread provides guidance on how to approach the problem mathematically.
rakshit gupta
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I am unable to find it.
 
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Hello Rakshit, welcome to PF :smile: !

Here is an example. But you are well advised to make your own drawing and work out the integral from the definition of moment of inertia $$I \equiv \int r^2 \, dm$$
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It is easier to do the integrals if you place the x-axis along the base of the pyramid, and the y-axis going vertically through the top apex.
Then you can use the parallel axis theorem to get the moment of inertia about the center of the pyramid.
 
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rakshit gupta said:
I am unable to find it.
I'm not surprised. What does "motion of inertia" even mean?

You can determine the second moment of area for a region which is an equilateral triangle, or the mass moment of inertia for a plate or thin lamina which has the shape of an equilateral triangle.

So which are you interested in finding?
 
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BvU said:
Hello Rakshit, welcome to PF :smile: !

Here is an example. But you are well advised to make your own drawing and work out the integral from the definition of moment of inertia $$I \equiv \int r^2 \, dm$$
--
SteamKing said:
I'm not surprised. What does "motion of inertia" even mean?

You can determine the second moment of area for a region which is an equilateral triangle, or the mass moment of inertia for a plate or thin lamina which has the shape of an equilateral triangle.

So which are you interested in finding?
For a thin lamina
 
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