Plant_Boy
- 15
- 1
I'm reading a number of papers, journals, reports and what not trying to grasp at what the actual definition of \tau.
\tau = \frac {m_{e}}{\rho e^{2} n}
Am I correct in thinking:
m_{e} - mass of an electron
\rho - resistivity
e - charge of electron
n - number of electrons per unit mass
In one I read it is Mean Free Time between Collisions of Electrons. Another states it is Relaxation Time. Are these two definitions dependent on whether you use a DC or AC energy source?
I understand from the equation as the mass in kilogram of an electron is divided by an ohm, kilogram meter squared per second{}^3 per ampere{}^2, times an ampere second times a number. The values cancel out to leave an ampere second{}^2 per meter{}^2.
Or,
\tau = (A s^2 m^{-2})
So, one amp takes s{}^2 seconds to decay into an area?
\tau = \frac {m_{e}}{\rho e^{2} n}
Am I correct in thinking:
m_{e} - mass of an electron
\rho - resistivity
e - charge of electron
n - number of electrons per unit mass
In one I read it is Mean Free Time between Collisions of Electrons. Another states it is Relaxation Time. Are these two definitions dependent on whether you use a DC or AC energy source?
I understand from the equation as the mass in kilogram of an electron is divided by an ohm, kilogram meter squared per second{}^3 per ampere{}^2, times an ampere second times a number. The values cancel out to leave an ampere second{}^2 per meter{}^2.
Or,
\tau = (A s^2 m^{-2})
So, one amp takes s{}^2 seconds to decay into an area?