What Is the Acceleration Constraint in This Pulley System?

Click For Summary

Homework Help Overview

The discussion revolves around a pulley system and the acceleration constraints associated with it. Participants are tasked with finding a relationship between the accelerations of three masses (m1, m2, and m3) in the system, as well as exploring the tension in the strings involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship a1y = -a2y and express confusion about how a3y fits into this equation. There are inquiries about the definitions of the variables used, particularly regarding the accelerations of the blocks.
  • Some participants suggest analyzing the system under specific mass conditions, such as assuming m2 = m3 and m1 = m2 + m3, to explore the implications on tension in the ropes.
  • Questions arise about the implications of changing the masses slightly and how that affects the system's balance and tension.

Discussion Status

The discussion is ongoing, with participants seeking clarification on variable definitions and relationships. There is a productive exploration of different scenarios involving mass relationships and their effects on tension, but no consensus has been reached on the acceleration constraints or the overall solution.

Contextual Notes

Participants are working with specific mass values provided in the problem statement, and there is an emphasis on understanding the relationships between the accelerations and tensions in the system. The original poster expresses difficulty in connecting the variables and understanding the implications of the assumptions made.

ezp0004
Messages
2
Reaction score
0

Homework Statement



Hello. I need help with a problem that deals with the acceleration constraint of a system (URL below is to an image of the system):

http://s3.amazonaws.com/answer-board-image/e8ee7c74-664f-4220-a394-fc2b3d5bc269.jpeg

The questions asked in the problem are as follows:

1) Find the acceleration constraint for this system. It should be a single equation relating a1y, a2y, and a3y. Hint: yA is not a constant.

2) Find an expression for the tension in string "A".

3) Using m1 = 2.5kg, m2 = 1.5kg, and m3 = 4kg, find a1y, a2y, and a3y.


Homework Equations



I need to find equation for a1y in terms of a2y and a3y. I know that a1y should be equal to -a2y. However, I do not understand how a3y relate to these. Newton's second law (force=mass*acceleration) should be the only other equation needed to solve this problem.

The Attempt at a Solution



Other than recognizing that a1y = -a2y, I am complete stuck on this problem. I would appreciate any and all help that you may be able to provide. Thanks in advance.
 
Physics news on Phys.org
ezp0004 said:

Homework Statement



Hello. I need help with a problem that deals with the acceleration constraint of a system (URL below is to an image of the system):

http://s3.amazonaws.com/answer-board-image/e8ee7c74-664f-4220-a394-fc2b3d5bc269.jpeg

The questions asked in the problem are as follows:

1) Find the acceleration constraint for this system. It should be a single equation relating a1y, a2y, and a3y. Hint: yA is not a constant.

2) Find an expression for the tension in string "A".

3) Using m1 = 2.5kg, m2 = 1.5kg, and m3 = 4kg, find a1y, a2y, and a3y.

Homework Equations



I need to find equation for a1y in terms of a2y and a3y. I know that a1y should be equal to -a2y. However, I do not understand how a3y relate to these. Newton's second law (force=mass*acceleration) should be the only other equation needed to solve this problem.

The Attempt at a Solution



Other than recognizing that a1y = -a2y, I am complete stuck on this problem. I would appreciate any and all help that you may be able to provide. Thanks in advance.
I am not clear on the variables you are using. Please explain what you mean by a1y, a2y, a3y etc. That is an acceleration x distance.

Assume that m2=m3 and m1=m2+m3. What would the tension be on the ropes? Then change the masses slightly and analyse the change.

AM
 
Last edited:
Andrew Mason said:
I am not clear on the variables you are using. Please explain what you mean by a1y, a2y, a3y etc. That is an acceleration x distance.

Assume that m2=m3 and m1=m2+m3. What would the tension be on the ropes? Then change the masses slightly and analyse the change.

AM

I believe that a1y, a2y, and a3y are referring to the accelerations of blocks m1, m2, and m3 in the 'y' direction. Other than that, all variables should be represented in the figure that I linked.

Using m2=m3 and m1=m2+m3, does this meant that the tensions on the ropes for m2 and m3 are the same and that the tension for the rope connected to m1 is twice that of the tension for ropes connected to m2 and m3? I'm not really sure what you are trying to get at. Since the masses are given in the third question (m1+m2=m3 but m1 does not equal m2).
 
ezp0004 said:
I believe that a1y, a2y, and a3y are referring to the accelerations of blocks m1, m2, and m3 in the 'y' direction. Other than that, all variables should be represented in the figure that I linked.

Using m2=m3 and m1=m2+m3, does this meant that the tensions on the ropes for m2 and m3 are the same and that the tension for the rope connected to m1 is twice that of the tension for ropes connected to m2 and m3? I'm not really sure what you are trying to get at. Since the masses are given in the third question (m1+m2=m3 but m1 does not equal m2).
If m1 = (m2+m3) and m2=m3, the system is in balance. Doing a free body diagram you can see that: 1. the tension in the rope through A is just m2g and the tension in the rope through B is m1g = (m2+m3)g

Now change it so that m2 and m3 differ by \Delta m and analyse that. (Hint: think of m2 on each side with an added mass \Delta m added to the one on the right (m3).

AM
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
25
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 98 ·
4
Replies
98
Views
7K
Replies
21
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
45
Views
7K
  • · Replies 8 ·
Replies
8
Views
12K