What Is the Acceleration of a Baseball at Its Highest Point?

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SUMMARY

The acceleration of a baseball at its highest point is solely due to gravity, which is approximately 9.81 m/s² downward. When a baseball is thrown upward, it experiences an upward acceleration while in the hand, but once released, the only force acting on it is gravity. Therefore, regardless of the ball's speed being zero at the highest point, its acceleration remains constant at -9.81 m/s² due to gravitational pull. Any upward acceleration provided during the throw does not negate the effect of gravity once the ball is in free fall.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of kinematics
  • Familiarity with gravitational acceleration (9.81 m/s²)
  • Concept of forces acting on an object in motion
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  • Learn about Newton's second law of motion and its applications
  • Explore kinematic equations for objects under constant acceleration
  • Investigate the role of air resistance in projectile motion
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lLovePhysics
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I'm confused with this problem:

A baseball is thrown straight upward. What is the ball's acceleration at its highest point?

I think that it would be gravity but its speed is 0 right?

When problems say that a ball is thrown up with an acceleration of 3 m/s^2, does the acceleration magnitude already include that of gravity? Because if not, wouldn't you need to subtract the 10m/s^2 of acceleration of gravity too?
 
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lLovePhysics said:
I think that it would be gravity but its speed is 0 right?
So? What does the ball's speed have to do with its acceleration?

When problems say that a ball is thrown up with an acceleration of 3 m/s^2, does the acceleration magnitude already include that of gravity?
Once the ball leaves your hand, the only force on it is gravity (ignoring air resistance) and thus its acceleration is g downward.

While the ball is in your hand you can push on it, giving it an upward acceleration.
 

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