What is the angle between the normals to the surface at two given points?

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Homework Help Overview

The discussion revolves around finding the angle between the normals to the surface defined by the equation xy = z² at two specific points: (1, 4, 2) and (-3, -3, 3). The problem is situated within the context of multivariable calculus and surface normals.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of the gradient of the surface and its evaluation at the given points to find the normals. There is a focus on the use of the dot product to determine the angle between these normals. Some participants express uncertainty about the correctness of the initial calculations and the method used to derive the normals.

Discussion Status

Several participants have provided insights into the approach of calculating the gradient and evaluating it at the specified points. There is acknowledgment of the need to clarify the method of finding the normals, and some participants are exploring the implications of the surface equation. No consensus has been reached, but there is a productive exchange of ideas regarding the calculations involved.

Contextual Notes

Participants are operating under the constraints of homework guidelines, which discourage the provision of complete solutions. There is an emphasis on showing effort before receiving assistance, and some participants have noted the importance of adhering to these rules.

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Homework Statement


find the angle between the normals to the surface xy=z2 at the points (1,4,2) and (-3,-3,3)


Homework Equations



none

The Attempt at a Solution


del S = 2zy i + 2zx j
and at the two points, del S = 16i+4j and del S = -18i-18j

using the dot product, i got cos theta = -5/(4*sqrt 34)

which is NOT the answer. Is my partial derivative equation right ? Please help.
 
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msslowlearner said:

Homework Statement


find the angle between the normals to the surface xy=z2 at the points (1,4,2) and (-3,-3,3)


Homework Equations



none

The Attempt at a Solution


del S = 2zy i + 2zx j
and at the two points, del S = 16i+4j and del S = -18i-18j

using the dot product, i got cos theta = -5/(4*sqrt 34)

which is NOT the answer. Is my partial derivative equation right ? Please help.

No, it isn't right. Write f = xy - z2 = 0 and calculate

∇f = <fx,fy,fz>
 
msslowlearner said:

Homework Statement


find the angle between the normals to the surface xy=z2 at the points (1,4,2) and (-3,-3,3)


Homework Equations



none

The Attempt at a Solution


del S = 2zy i + 2zx j
and at the two points, del S = 16i+4j and del S = -18i-18j

using the dot product, i got cos theta = -5/(4*sqrt 34)

which is NOT the answer. Is my partial derivative equation right ? Please help.
It doesn't look right to me. I don't understand how you got what you did.

The equation for your surface is xy = z2, or equivalently, xy - z2 = 0. The implied function here is F(x, y, z) = xy - z2. Your surface is the set of points (x, y, z) for which F(x, y, z) = 0.

For the gradient, calculate \nabla F and evaluate it at the two points. Each will give you a vector. From these vectors you can determine the angle, using the approach that you showed above.
 
sorry .. should have checked the partial derivative part. I thought i got the idea wrong. Its heartening to know I'm on the right track atleast :) thankyou
 
stallionx,

Please don't post complete solutions.

See the rules for posting Homework Help:
"On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made."

It may still be possible to Edit your post.
 
SammyS said:
stallionx,

Please don't post complete solutions.

See the rules for posting Homework Help:
"On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made."

I am sorry, Sir.
 
For a tangent plane equation to the z=f(x,y))

z-z0=(delz/delx)(x-x0)+(delz/dely)(y-y0)

which says the normal vector is < delz/delx , delz/dely , -1>

Find those two vectors for 2 different points

Dot product these vectors

V1 * V2 = length(V1)*length(V2) * Cos(theta)

Theta = ACOS ( V1*V2)/ ( product of lengths of perpendicular/ orthogonal vectors )
 
stallionx said:
For a tangent plane equation to the z=f(x,y))

z-z0=(delz/delx)(x-x0)+(delz/dely)(y-y0)

which says the normal vector is < delz/delx , delz/dely , -1>

Find those two vectors for 2 different points

Dot product these vectors

V1 * V2 = length(V1)*length(V2) * Cos(theta)

Theta = ACOS ( V1*V2)/ ( product of lengths of perpendicular/ orthogonal vectors )

DOT PRODUCT can be found from coordinates multiplication and addition

CASE : (x,y,z) dot (a,b,c) is xa+by+cz
 

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