What is the angle of the nth O in a decreasing rate?

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Homework Help Overview

The discussion revolves around determining the angle subtended by a series of equal-length segments (denoted as O1, O2, O3, etc.) from a point P. The original poster notes that as one moves down the series of O's, the angles decrease at a decreasing rate, leading to the question of how to calculate the angle for the nth O.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss using the cosine rule and tangent function to relate the angles and lengths involved. There are attempts to clarify the relationships between the angles of consecutive O's and the geometry of the situation.

Discussion Status

Some participants have suggested using trigonometric functions to approach the problem, while others express uncertainty about their understanding of these concepts. There is an ongoing exploration of how to relate the angles and lengths without complete information, and multiple interpretations of the problem are being considered.

Contextual Notes

The original poster indicates a lack of information regarding the lengths of the segments and emphasizes that only the lengths of O and the angles at point P are known. This constraint affects the approaches being discussed.

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Homework Statement


Look at the image.All the O's are of equal length.O1=O2=O3 etc.Angles are subtended from two ends of An O to point P.As you see,O1's angle is larger than O2 ant )2's angle is larger then O3 and so on.
As you Go down the O's(i.e. O1,O2,O3 etc),the angle subtented by the O's Decrease and that too with a decreasing rate.
What would be the angle of nth O.

See the image Clearly please..

Homework Equations


a+d(n-1)
ar^(n-1)


The Attempt at a Solution


As the angles decrease with decreased rate,The Formulas are not usable.
What should I do?Angles are not even inversely proportional to O's.
 

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You can use the cosine rule. Lengths of two "rays" can be calculated from Pythagorean theorem.
 
szynkasz said:
You can use the cosine rule. Lengths of two "rays" can be calculated from Pythagorean theorem.
What could be the angle of nth O?
And I haven't studied Cosine rule yet.I am In Gr 9.
 
Rays are hypotenuses of right angles so you can use tangent function instead. The angle of nth O is a difference of angles of nth and n-1th triangle.
 
szynkasz said:
Rays are hypotenuses of right angles so you can use tangent function instead. The angle of nth O is a difference of angles of nth and n-1th triangle.
I don't Understand
 
Let ##PO## be the segment from ##P## to the line of ##O##'s Together with ##a## and ##O_1## it makes a right triangle so you can calculate ##\tan\alpha_{\small O_1}##
 
Just to make sure everyone's on the same page: adjacent, do you know trigonometric functions (Sine, Cosine, Tangent)?
 
Strants said:
Just to make sure everyone's on the same page: adjacent, do you know trigonometric functions (Sine, Cosine, Tangent)?
Yes.But
Only sineθ=Opposite/Hypotenuse
Cosineθ=Adjacent/Hypotenuse
a Tangentθ=Opposite/Adjacent
But that's for Right angle triangle only.Right?

Assume that we don't know any thing about the length of the lines.Only Length of O and Angles(on the side of P) are given.We are to calculate,for example,For O1,the angle is this much.For O2 The angle would be that much.Then For On what would be the angle?
 
Last edited:
##PO,2O,b## also makes right triangle. So the angle for 2nd ##O## is ##\alpha_{\small O_2}-\alpha_{\small O_1}##
 

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