What is the angular velocity of a hinged pole as a truck accelerates?

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The discussion focuses on calculating the angular velocity of a 3.6 m pole hinged to a truck bed as the truck accelerates at 0.90 m/s². The pole is released from a vertical position and reaches a horizontal position. Key equations mentioned include Vr=0, Vtheta=r*Theta, Ar=-r*Theta(dot)², and Atheta=r*Theta(double dot). The challenge lies in incorporating the truck's acceleration into the angular motion equations to derive the correct angular velocity.

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The uniform 3.6 m pole is hinged to the truck bed and released from the vertical position as the truck starts from rest with an acceleration of 0.90 m/s2. If the acceleration remains constant during the motion of the pole, calculate the angular velocity of the pole as it reaches the horizontal position.

I believe I know this question however I wanted to be sure
 
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Please go ahead and post your solution so far, then.
 
Never mind my solution was wrong although I think that using the equations

Vr=0
Vtheta=r*Theta
Ar=-r*Theta(dot)^2
Atheta=r*Theta(double dot)

However i am unsure as to how to add the trucks acceleration into the solution.
 

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