ucbugrad Messages 4 Reaction score 0 Thread starter Jan 26, 2012 #1 What is the expectation value of cosine squared, namely <cos^2(t)>?
Tarantinism Messages 28 Reaction score 0 Jan 26, 2012 #2 cos2x = (1+cos(2x))/2 Integration leads to 0,5 (averaged over the lenght)
mathman Science Advisor Homework Helper Messages 8,130 Reaction score 575 Jan 26, 2012 #3 Another approach: cos2(x) + sin2(x) = 1. Both terms have the same average, so the average for cos2(x) = 1/2.
Another approach: cos2(x) + sin2(x) = 1. Both terms have the same average, so the average for cos2(x) = 1/2.