What is the average force on the tennis ball?

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SUMMARY

The average force exerted on a tennis ball during a serve can be calculated using Newton's Second Law. Given that the ball reaches a speed of 62.0 m/s from rest in 0.0200 seconds and has a mass of 0.0600 kg, the average acceleration is 3100 m/s². Consequently, the average force on the ball is 186 N, derived from the formula F = ma, where F is force, m is mass, and a is acceleration.

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A tennis ball may leave the racket of a top player on the serve with a speed of 62.0 m/s. If the ball's mass is 0.0600 kg and it is in contact with the racket for 0.0200 s, what is the average force on the ball?
 
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You must deduce the average force from the average acceleration (Newton'S 2 law)

if the ball went from 0 to 62m/s in 0.0200 s, then what is the average accel?

btw - you're in the wrong forum. This is the math forum and yours is a physics question. try "Introductory physics" next time.
 

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