What Is the Average Power Output of an Elevator Motor During Acceleration?

[mkwok]

Homework Statement

A 750 kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising =

Homework Equations

W=Fd

The Attempt at a Solution

(a)
\sumF = T-mg=ma
Vavg=1.75/2 == > a=1.75/2/3
=> T- 750(9.8) = (750)(1.75/2/3)
T=7568.75N

W=T*d
d=Vavg*t=1.75/2*3
W=7568.75*1.75/2*3=19867.97Am I doing this correctly?

(b) how do I do part b?I don't think I did part a correctly because I got a much different value... and the internet assignment said I am very close

 

[PhanthomJay]

Homework Statement

A 750 kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?


(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising =

Homework Equations

W=Fd

The Attempt at a Solution

(a)
\sumF = T-mg=ma
Vavg=1.75/2 == > a=1.75/2/3
=> T- 750(9.8) = (750)(1.75/2/3)
T=7568.75N

W=T*d
d=Vavg*t=1.75/2*3
W=7568.75*1.75/2*3=19867.97


Am I doing this correctly?

(b) how do I do part b?


I don't think I did part a correctly because I got a much different value... and the internet assignment said I am very close

Part a you calculated the work correctly. But the question asks for the average power, not the work done. You must note the formula for power as a function of work and time.
For part b, it is simplest to use the formula P=Fv, what is F in this case??

 

[mkwok]

I guess F is just the tension? therefore
F = 7568.75N
will v be the final velocity or the average velocity?

 

[PhanthomJay]

I guess F is just the tension? therefore
F = 7568.75N
will v be the final velocity or the average velocity?

F is the tension, but since the elevator is cruising at constant speed, and not accelerating, the F will not be 7568N. What is F at constant velocity?