What is the average speed of a particle with given position and time data?

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Homework Help Overview

The problem involves calculating the average speed of a particle based on its position function over a specified time interval. The position is given as a quadratic function of time, and the discussion revolves around finding the average speed from the calculated average velocity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss differentiating the position function to find velocity and integrating the absolute value of velocity to determine average speed. There are attempts to clarify the integration process and the handling of negative values in the velocity function.

Discussion Status

Participants are actively engaging with the problem, exploring various methods to calculate average speed. Some guidance has been offered regarding the integration of the absolute value of velocity, and there are indications of multiple interpretations and attempts to resolve discrepancies in calculations.

Contextual Notes

There is mention of specific time intervals and conditions under which the velocity changes sign, which affects the integration process. Participants express uncertainty about their calculations and seek clarification on the correct approach.

Casimi
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Homework Statement


The position of a particle as a function of time is given by x = (-5.06 m/s)t + (3.05 m/s2)t2. Calculate the average velocity of the particle from t = 0 to t = 1.20 s.
-1.40 m/s (this is correct, from my calculations)

2nd part: Calculate the average speed from t = 0 to t = 1.20 s


The Attempt at a Solution


I have tried this for hours and cannot arrive at the correct answer for the second part. I tried taking the total distance and dividing by the total time. Could someone please point me in the right direction to find average speed? I have even tried differentiation.

Any assistance would be appreciated. Thanks!
 
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you can differentiate to get the velocity then take the integral of its absolute value then divide it by time
 
I tried that but I am still not arriving at the correct answer. I arrive at a number far larger than it should be.

I cannot figure out what I am doing wrong.
 
did you make sure to separate it into two integral when you integrated the absolute value one negative and one positive?
 
(-5.06+6.10t) - that is my answer after differentiating. Integrating the absolute value, I have 5.06t+3.05t^2 with integral limits of 0 to 1.20. When I put the values in the integral, I get 9.456 and when divided by 1.2, I get 7.88 which is not the correct answer.
 
I am saying as integral the absolute value
you must know if when v = 0 lies in your interval
-5.06+6.10t=0
t=5.06/6.10 this lies in the interval so you make the integral negative here and positive from it to 1.2
 
Yes, I tried that and am still not arriving at the right answer. 5.06/6.10 will give .82. If I integrate from -5.06t+3.05t^2 [0 to .82] + 5.06t+3.05t^2 [.82 to 1.2] I am still going to get :
5.06t +3.05t^2 [0 to 1.2]? Please help me out.
 
what you do is get the integral from 0 to .82 (5.06-6.1t)dt
+ the integral from .82 to 1.2 (-5.06 +6.1t)dt
 
I came up with 2.51m/s but it is still showing as incorrect. Is this the solution that you arrived at?
 
  • #10
did you divide it by the time?
 
  • #11
Thank you! You just saved my grade!
 

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