What is the Charge and Error in a Parallel Plate Capacitor?

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SUMMARY

The charge on a parallel plate capacitor with a capacitance of C = 8.5±1 μF and a potential difference of V = 4.5±0.4 Volts is calculated using the formula Q = C * V. The resulting charge is Q = 38.25±4.25 μC. To calculate the error in the charge, the percentage errors in capacitance and voltage are added, following the formula for error propagation in multiplication and division.

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A capacitor with capacitance of C = 8.5±1 μF has a potential difference of V = 4.5±0.4 Volts. What are the charge on the capacitor and the error in this value, in μC?

To find charge I just use Q = C*V correct? And how do I calculate the error?

Thank you!
 
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For s=ab
[tex]\frac{\delta s }{s}= \frac{\delta a}{a} + \frac{\delta b}{b}[/tex]

Where [itex]\delta s[/itex] is the error in s and similiarly for a and b.
 
Another way to say that is that for multiplying and dividing, the % errors in quantities are added.
 

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