What is the charge on the left-hand plate of C4?

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The charge on the left-hand plate of capacitor C4 is determined to be -24 μC based on the principles of charge conservation in a circuit with identical capacitors. Given that the charge on the left-hand plate of C1 is +24 μC, the left plate of C4, which is adjacent to the negative terminal of the battery, must exhibit an equal and opposite charge. This conclusion is supported by the direct connection of the left plates of C1 and C4 to the EMF source, reinforcing the necessity for charge balance in the system.

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The capacitors in the circuit below are all identical. The EMF of the battery is unknown.
http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys212/oldexams/exam1/sp08/fig24.gif

If the charge on the left-hand plate of C1 is +24 μC, what is the charge on the left-hand plate of C4?

(a) Q4 = -24 μC
(b) Q4 = -12 μC
(c) Q4 = 0
(d) Q4 = +12 μC
(e) Q4 = +24 μC

What's the concept behind this? Is it -24 uC because the left plate of C4 is next to the negative terminal of the battery?
 
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Only two left plates are connected directly to E. According to conservation of charges the charges on two plates must be equal and opposite.
 

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