What is the Coefficient of Rolling Friction for a Tire Under Low Pressure?

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SUMMARY

The coefficient of rolling friction for a tire under low pressure can be calculated using the distances traveled by two bicycle tires inflated to different pressures. The tire at 40 psi traveled 18.7 meters, while the tire at 105 psi traveled 93.3 meters, both starting at an initial speed of 3.60 m/s. The correct calculation involves using the formula Vf^2 = Vi^2 + 2ax, where the acceleration 'a' is derived from the distance traveled until the speed is halved. The recalculation confirms that the coefficient of rolling friction for the low-pressure tire is accurately determined by considering the correct distance for the speed reduction.

PREREQUISITES
  • Understanding of basic physics concepts such as acceleration and friction.
  • Familiarity with the equations of motion, specifically Vf^2 = Vi^2 + 2ax.
  • Knowledge of how to calculate coefficients of friction, particularly rolling friction.
  • Ability to perform unit conversions, particularly pressure from psi to relevant units if necessary.
NEXT STEPS
  • Review the principles of rolling friction and its dependence on tire pressure.
  • Learn how to apply the equations of motion to real-world scenarios involving friction.
  • Investigate the effects of tire pressure on vehicle performance and safety.
  • Explore advanced topics in dynamics, including energy loss due to friction in different materials.
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of tire performance under varying pressure conditions.

tmilla
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Homework Statement



Two bicycle tires are set rolling with the same initial speed of 3.60 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes 18.7m ; the other is at 105 psi and goes 93.3m . Assume that the net horizontal force is due to rolling friction only.

What is the coefficient of rolling friction for the tire under low pressure?

Homework Equations



Vf^2=Vi^2 +2ax
Ur=a/g ?? (Ur= coefficient of rolling friction

The Attempt at a Solution



1st Tire:
-(3.60)^2/(2*18.7) = a = -.3465

.3465/9.81=Ur

This is wrong, but I honestly have no idea what to do. Help is GREATLY appreciated! :)
 
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Welcome to PF.

I would start off by recalculating your expression for tire 1.

Reread the problem statement. The distance of 18.7 is when |v| = 1/2*|Vo|, not when it goes to 0.
 
ahh, missed that little fact. Got the right answer now :)
Thank you!
 

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