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[SOLVED] Rolling Friction
Rolling Friction. Two bicycle tires are set rolling with the same initial speed of 3.30 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes 17.5 m; the other is at 105 psi and goes 92.4 m. Assume that the net horizontal force is due to rolling friction only.
What is the coefficient of rolling friction usubr for the tire under low pressure? For the second one?
Take the free fall acceleration to be g = 9.80 m/s^2.
F=ma
v^2 = vi^2 + 2a (x-xi)
w=ma
First, I think we should find acceleration of the tires.
I used the following: v^2 = vi^2 + 2a (x-xi)
1.65^2= 3.30^2 + 2a(17.5-0)
a = -3.3106
where do I go from here, ( that is if everything I did thus far is correct) :S
Homework Statement
Rolling Friction. Two bicycle tires are set rolling with the same initial speed of 3.30 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes 17.5 m; the other is at 105 psi and goes 92.4 m. Assume that the net horizontal force is due to rolling friction only.
What is the coefficient of rolling friction usubr for the tire under low pressure? For the second one?
Take the free fall acceleration to be g = 9.80 m/s^2.
Homework Equations
F=ma
v^2 = vi^2 + 2a (x-xi)
w=ma
The Attempt at a Solution
First, I think we should find acceleration of the tires.
I used the following: v^2 = vi^2 + 2a (x-xi)
1.65^2= 3.30^2 + 2a(17.5-0)
a = -3.3106
where do I go from here, ( that is if everything I did thus far is correct) :S
