What is the coefficient of static friction in this block and string setup?

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SUMMARY

The coefficient of static friction for a 4.0 kg block of wood on a table, with a maximum hanging mass of 1.8 kg, can be calculated using the equation Fs = μFn. The normal force (Fn) is determined to be 39.2 N, derived from the weight of the block (4.0 kg multiplied by 9.8 m/s²). The tension in the string, which equals the gravitational force on the hanging mass, is also 17.64 N (1.8 kg multiplied by 9.8 m/s²). Thus, the coefficient of static friction (μ) is calculated as μ = Fs/Fn = 17.64 N / 39.2 N, resulting in a coefficient of approximately 0.45.

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Homework Statement




A 4.0 kg block of wood sits on a table. A string is tied to the wood,
running over a pulley and down to a hanging object. The greatest mass that can be
hung from the string without moving the block of wood is 1.8 kg. Calculate the coefficient
of static friction between the block of wood and the table.

4.0 kg and 1.8 kg- mass

Homework Equations



Fs=μFn

The Attempt at a Solution



so i assume the block isn't moving so fnet would be 0, fn=fg so 4.0(9.8) ---> 39.2

i don't have fs and mew so how am i supposed to solve this?
 
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There are 2 forces acting horizontally on the block on the table. One is the tension force that can be calculated by looking at the forces on the hanging mass.
 
It is always best to create a diagram and Net force equations for each individual object. You are right in that F=0 but this also tells you that whatever force is pulling at the block of wood, there is an equal and opposite force that stops it from moving. This is crucial piece of information for your problem.
 
so if i calculate fg=mg on the hanging mass, would the force of tension be the same as fg?
 
jjesiee said:
so if i calculate fg=mg on the hanging mass, would the force of tension be the same as fg?
Sure!
 

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