nrqed
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Ok! I actually have wanted to present the same results as you are obtaining but using my point of view (starting from the many-body aspect) for a while. I kow it would help *me* clarify my thoughts, even if nobody else reads me!Eye_in_the_Sky said:Those two posts are intended for all readers of this thread ... especially me.
I agree 100%!So many points are being made in this thread, and I want to see how they stand when "relativity" is taken OUT of the picture. Once things have been properly understood there – in the nonrelativistic domain – then it makes sense to put the "relativity" back in and see just how things change.
yes, it is a good idea. As I sadi above, I have wanted to do this myself for a while now, using the approach I prefer.But, in order to see things clearly (albeit, in only a nonrelativistic 'light'), I needed to work out the details. And in order to discuss those details with the group here in the forum, I felt it would be helpful to post them in a clear and concise way.
Oh! Well, it's nice to hear you say that! Because my point is almost exclusively about pedagogy. I am not disputing that the traditional approach is flawed in any way, of course. I am mostly complaining about the way textbooks (whose first goal is to *teach*) almost invariably start with "well, let's quantize classical fields that have never been observed now".Like I said, let's take "relativity" OUT of the picture. Then, the question becomes one about the canonical quantization of the Schrödinger field and its connection to NRQM. The "logic" of this connection is purely on the level of abstract formalism, and as far as pedagogy is concerned, I agree with you 100% – this is not the way to begin.
I will get back to some of the things you mentioned in your post, but for now I just wanted to ask one thing..
My question is obviously: why not takeSeek an action functional S[ψ,ψ*] which pays complete respect to the symmetry between ψ and ψ*. Specifically, look for S such that
δS = ∫dt ∫dx [ (δψ*)(i∂t - Hx)ψ + (δψ)(-i∂t - Hx)ψ* ] .
Then, 'break' that symmetry by means of a judicious integration by parts applied to the second term of the integrand (once for the (δψ)∂tψ* subterm, and twice for the (δψ)∂x2ψ* subterm), so that the variation of the action becomes
δS = ∫dt ∫dx [ (δψ*)(i∂t - Hx)ψ + ψ*(i∂t - Hx)(δψ) ]
= ∫dt ∫dx δ [ ψ*(i∂t - Hx)ψ ] .
δS = ∫dt ∫dx [ (δψ)(i∂t - Hx)ψ + (δψ*)(-i∂t - Hx)ψ* ?
Regards
patrick