What is the contact force between the blocks?

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SUMMARY

The discussion centers on calculating the contact force between two blocks on a frictionless tabletop, subjected to an external force, F, resulting in a constant acceleration of a = 2.45 m/s². The confusion arises from the misconception that the contact forces between the blocks are different, which is clarified through the understanding of Newton's Third Law. The contact force exerted by block 1 on block 2 is equal in magnitude and opposite in direction to the force exerted by block 2 on block 1, confirming that there is only one contact force acting between the two blocks.

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Marioqwe
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Homework Statement



Two blocks are in contact on a frictionless, horizontal tabletop. An external force, F, is applied to block 1, and the two blocks are moving with a constant acceleration a = 2.45 m/s^2.

Homework Equations



what is the contact force between the blocks?

The Attempt at a Solution



I'm a little confused with the question. I see that the force that block 1 exerts on block 2 is different from the one that block 2 exerts in block 1. Does that mean that I have two different contact forces?
 
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Marioqwe said:
I'm a little confused with the question. I see that the force that block 1 exerts on block 2 is different from the one that block 2 exerts in block 1. Does that mean that I have two different contact forces?

In what way are they different? Can you show your reasoning or better yet, your calculation?
 
gneill said:
In what way are they different? Can you show your reasoning or better yet, your calculation?

I see my mistake. I was somehow mistaking it with static friction.
 

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