What is the correct centroid for a semicircle?

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SUMMARY

The correct centroid for a semicircle is calculated as (4r)/(3π), which represents the average y-coordinate of the semicircular area. This conclusion is supported by integral calculus, specifically the formula (1/A) ∫[y * 2√(1 - y²) dy] from 0 to 1. The confusion arises from mixing the centroid of a semicircular area with that of a semicircular arc, which are distinctly different as noted in the referenced Wikipedia page.

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lizzyb
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The centroid of a semicircle is noted at being (4r)/(3 pi) - http://en.wikipedia.org/wiki/List_of_centroids. However, when I did the work myself using the integral of y da over the area, I came up with (2 r)/(pi). I figured I was doing something wrong so sought out someone else's work and found this:

pg=PA164&img=1&zoom=3&hl=en&sig=ACfU3U3CWQGo0xQTBkdM18w7Hm8OBCZWPQ&ci=19%2C22%2C934%2C593&edge=0.png


http://books.google.com/books?id=P7...&dq=analytically centroid semicircle&pg=PA164

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The correct answer is 4r/3pi, if what you are after is the average y-coordinate. This can be calculated fairly easily by doing this:

(1/A) S[y*2sqrt(1-y^2)dy] from 0 to 1.

I think you are confusing a semicircular area with a semicircular arc. Both appear on the Wikipedia page with centroids. The excerpt you posted clearly refers to the case of a semicircular arc, not an area.
 

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