What Is the Correct Integrating Factor for the Equation ay dx + bx dy = 0?

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SUMMARY

The discussion centers on finding the correct integrating factor for the exact differential equation ay dx + bx dy = 0. The user initially calculated the integrating factor as x((a-b)/b) but found discrepancies with the book's answer of x^(a-1)y^(b-1). The conversation emphasizes the necessity of normalizing the equation before determining the integrating factor, using the method of inspection and the formula for integrating factors in normalized forms.

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EXACT equation !

hi! to all
I want little help about exact equation..
that the given equation is
>> ay dx + bx dy= 0
I had solved and found integrating factor of all of my equations by formula
P(x) = My-Nx/N
but for this equation I have got IF for this equation is x((a-b)/b) and after multiplying this factor by equation I can't get exact equation once again :mad:
and in book answers IF for this equation is x^a-1.y^b-1
So., can anyone tell me how can I solve this eq by method of inspection >>
pleasezz help me!
 
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Why not just divide by xy?
 


In order to determine what the integrating factor is you must first normalize the equation.
[tex]\frac{dy}{dx}+P(x)y=f(x)[/tex]
is an example of a normalized differential equation, the IF being
[tex]e^{\int P(x)dx}[/tex].

Does this help?
 

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