What Is the Correct Objective Function for Maximizing Package Volume?

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Homework Help Overview

The discussion revolves around maximizing the volume of a rectangular package subject to specific constraints related to its dimensions. The constraints include a maximum length of 128 inches and a condition involving girth, which is defined as the perimeter around the package.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of the objective function for maximizing volume, with some confusion about the correct equations to use. There are questions about the definition of girth and its implications for the problem setup.

Discussion Status

The discussion is ongoing, with some participants expressing uncertainty about the equations proposed for the objective function and constraints. There is a mix of attempts to clarify definitions and approaches, but no consensus has been reached on the correct formulation.

Contextual Notes

Participants note discrepancies in the definitions of girth and dimensions, and there is a mention of the need to adhere to the constraints provided by the parcel service. The original poster's understanding of the problem setup is questioned, indicating potential misunderstandings in the formulation of the problem.

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Homework Statement


A particular parcel sercive will accept only packages with length no more than 128 inches and length plus girth(xz)(width times height) no more than 145 inches.

What are the dimensions of the largest volume package the parcel service will accept?

This is the problem, but I just need to figure/know the objective equation and subject equation.
Do i use 2zx+2xy+2yz as my objective function and for my subject function would it be something like zx-17=0?

NOTICE: THIS IS A RECTANGULAR BOX

Homework Equations



Using Lagrange Multipliers
A=xy+xz+yz

The Attempt at a Solution



considering that i know that the area function is 2zx+2xy+2yz
Do i use 2zx+2xy+2yz as my objective function and for my subject function would it be something like zx-17=0?
 
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hi mathnoob123

I'm not sure where you got that equation from

what is the volume of a package? this is what you're trying to maximise...

then the constraints are as given, you can have more than one

what is girth? are you sure is just not width as it is given in inches not a areal unit...
also you may have to be careful about x>y>z in defining length, width etc.
 
I have successfully solved this problem. Thank you to all my fans. I am slowly, but surely becoming a powerful mathmatician. Muuuuuuhahahahaahhahahha!
 
MathNoob123 said:

Homework Statement


A particular parcel sercive will accept only packages with length no more than 128 inches and length plus girth(xz)(width times height) no more than 145 inches.
The words and the expressions don't match here. The girth is how far around the package is. If the longest dimension of the package is z, then the girth would be 2x + 2y.
MathNoob123 said:
What are the dimensions of the largest volume package the parcel service will accept?

This is the problem, but I just need to figure/know the objective equation and subject equation.
Do i use 2zx+2xy+2yz as my objective function and for my subject function would it be something like zx-17=0?
No and no. What you show for your objective function--2zx+2xy+2yz-- is just the area of the 6 sides of the package. And I have no idea where zx - 17 = 0 comes from.
MathNoob123 said:
NOTICE: THIS IS A RECTANGULAR BOX

Homework Equations



Using Lagrange Multipliers
A=xy+xz+yz

The Attempt at a Solution



considering that i know that the area function is 2zx+2xy+2yz
Do i use 2zx+2xy+2yz as my objective function and for my subject function would it be something like zx-17=0?

What you want to do is maximize the volume of the package (xyz) subject to the length restraint and the girth restraint.

I'm glad you were able to solve this problem successfully. However, the work shown here would not lead to a successful conclusion, as far as I can see.
 

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