- #1

- 1,752

- 143

I never used radius r in my answer. This book usually doesn't thrown in irrelavant information in the questions. Did I do this right?

[tex]\begin{array}{l}

I = \left| {\frac{Q}{t}} \right| \\

\\

t = \frac{d}{v} = \frac{{2\pi }}{\omega } \\

\\

I = \left| {\frac{Q}{{\left( {\frac{{2\pi }}{\omega }} \right)}}} \right| = \left| {\frac{{Q\omega }}{{2\pi }}} \right| = \left| {\frac{{ - e\omega }}{{2\pi }}} \right| = \frac{{e\omega }}{{2\pi }} \\

\\

\frac{{1.602 \times 10^{ - 19} {\rm{C}} \times 2 \times 10^{16} {\rm{rad/s}}}}{{2\pi }} = 5.1 \times 10^{ - 4} {\rm{C/s = }}5.1 \times 10^{ - 4} {\rm{A}} \\

\end{array}[/tex]