MHB What is the definition of lim sup and how is it related to subsequential limits?

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The discussion clarifies the definition of the limit superior (lim sup) of a sequence of real numbers, defined as the supremum of the set of all subsequential limits of that sequence. The formula presented, $$\lim \text{sup } s_n = \text{sup } E$$, indicates that the lim sup is the supremum of the set E, which consists of subsequential limits. Participants note that proving a definition is unnecessary, as there are multiple equivalent definitions for lim sup. The conversation suggests consulting additional resources for further understanding rather than attempting to redefine established concepts. Overall, the lim sup is a crucial concept in understanding the behavior of sequences in mathematical analysis.
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Let $s_n$ be a sequence of real numbers and define $E$ to be the set of all subsequential limits of $s_n$ in the real extended line. Then we define the following

$$\lim \text{sup } s_n = \text{sup } E$$​

For some reason I don't quite understand the above formula , do we need to prove it ? It would be nice if you give some examples.
 
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ZaidAlyafey said:
Let $s_n$ be a sequence of real numbers and define $E$ to be the set of all subsequential limits of $s_n$ in the real extended line. Then we define the following
$$\lim \text{sup } s_n = \text{sup } E$$​
For some reason I don't quite understand the above formula , do we need to prove it ? It would be nice if you give some examples.

We really don't prove a definition. There are many equivalent ways to define lim sup.
But there is no point in reinventing the wheel. Have a look at this page.
 
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We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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