What is the depth of a merged river with given stream dimensions and speeds?

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SUMMARY

The discussion focuses on calculating the depth of a merged river formed by two streams with specified dimensions and speeds. The first stream has a width of 9.3 m, depth of 4.3 m, and a current speed of 2.5 m/s, while the second stream is 6.8 m wide, 4.0 m deep, and flows at 2.7 m/s. The merged river has a width of 10.2 m and a current speed of 2.7 m/s. The solution involves applying the continuity equation, stating that the sum of the flow rates of the two streams equals the flow rate of the river.

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mbrmbrg
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Homework Statement



Figure 14-43 shows the merging of two streams to form a river. One stream has a width of 9.3 m, depth of 4.3 m, and current speed of 2.5 m/s. The other stream is 6.8 m wide and 4.0 m deep, and flows at 2.7 m/s. The width of the river is 10.2 m, and the current speed is 2.7 m/s. What is its depth?

Homework Equations



[tex]R_v=Av=constant[/tex]

[tex]A_1v_1=A_2v_2[/tex]

The Attempt at a Solution



Sure, the rate flow should be constant for an ideal river of varying cross-sectional area, but I don't understand what to do when more fluid is added. Since two streams are merging, do I say that [tex](A_{stream 1})(v_{stream1})+(A_{stream2})(v_{stream2})=(A_{river})(v_{river})[/tex]?
 

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mbrmbrg said:
Since two streams are merging, do I say that [tex](A_{stream 1})(v_{stream1})+(A_{stream2})(v_{stream2})=(A_{river})(v_{river})[/tex]?
Looks good to me. That's conservation of mass (the continuity equation) in action.
 
Thank you!
 

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