What is the derivative equation for a continuously differentiable function?

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SUMMARY

The discussion centers on determining the derivative equation for the piecewise function \(\phi\), defined as \(\phi(x) = 1\) for \(x \leq 0\), \(\phi(x) = 1 - 3x^2 + 2x^3\) for \(0 < x < 1\), and \(\phi(x) = 0\) for \(x \geq 1\). It is established that \(\phi\) is continuously differentiable due to the limits at the boundaries being equal, specifically \(\lim_{x \to 0} \phi(x) = 1\) and \(\lim_{x \to 1} \phi(x) = 0\). The derivative will also be piecewise, reflecting the structure of the original function.

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Homework Statement


Given the function:
1, x≤0;
[itex]\phi[/itex]={1-3x^2+2x^3, 0<x<1;
0, x≥1.
Show that [itex]\phi[/itex] is continuously differentiable and provide its equation

Homework Equations





The Attempt at a Solution


I have figured out that it is continuously differentiable because the limit as x approaches 0 is 1, and as it approaches 1 it is zero; thus there is no discontinuities. However, what would the derivate equation be? Thanks
 
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hi swhww3! welcome to pf! :smile:
swhww3 said:
I have figured out that it is continuously differentiable because the limit as x approaches 0 is 1, and as it approaches 1 it is zero; thus there is no discontinuities.

you've only proved that it is continuous
However, what would the derivate equation be?

the equation for the derivative will be in three parts, like the original equation :wink:
 

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